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#### nismopimp

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It'll be shorter in length AND in throw.CLSo1A said:it will be shorter in length but not in throw.

(Draw it on paper)

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Think of it in the extreme, cut the shaft so it only sticks out 1" above the pivot ball.

You telling me that the throw will still be the same distance?

You can prove this to yourself. Instead of shifting by grabbing the shift knob, grab the shifter halfway up.

Yes, this comes up ALL the time. Why buy something when you can mod your own for FREE by moving and pinning the pivot ball and if you desire also cut the shaft shorter.

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Oh geeze, if you're going to use the line "it isn't a difficult concept" at least get it right guys, this is not hard but yes you are all screwing it up.200sx se-r-t said:ok gents... this isnt a difficult concept if you cut the shaft it does not lessen your throw it is basic geometry with e leaver... the part of the shifter that makes for a shorter throw is the throat...

The end of the rod BELOW the ball will ALWAYS travel the same distance because the throw your shift forks and rods in your transmissions move will never change. Agreed?

So, how you make the end of the rod ABOVE the ball move a shorter distance and have the end of the rod BELOW the ball move the same distance is either by

1- increasing the length of the rod that is BELOW the ball or

2- shortening the length of the rod ABOVE the ball or

doing both #1 and #2.

You can move the pivot ball higher (shortens rod above ball and lengthens it below.)

You can cut the rod ABOVE the ball

You can cut the rod below the ball and weld in an extension.

Most aftermarket short shifters extend the rod below the ball to retain the stock height of the shift knob. My 1991 the shift knob is way too tall stock. I cut out 1/2" of the shaft above the ball (removed below the threads to retain the stock knob - re-tig'd), and then relocated the stock pivot ball 1/2" higher and pinned it.

Ended up with a really short throws AND a shorter shift knob in height too . ( a whopping 1" shorter in height)

Can't do word problems? How about some math.

L1 = length above fulcrum

D1 = distance end above fulcrum moves

L2 = length below fulcrum

D2 = distance end below the fulcrum moves (which is a constant in this case because of the tranny shift rod /forks.)

equation for lever arms about a pivot is

L1/L2 = D1/D2

Again D2 is a constant because of the tranny.

Solving for D1, you get D1 = (D2*L1)/L2

So if L2 remains constant (you don't change the length below the ball) and if L1 decreases (you cut the shaft above the ball) then D1 decreases.

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The distance your hand will travel will decrease as you cut down the shifter. So, if that is what you consider a shorter throw, you are correct. You are physically moving your hand a shorter distance. If you need proof of this, simply use your imagination and lengthen the shifter by 10 feet. The distance of the "throw" would be rather large.

However... cutting down the shifter will not change the angles involved. Only the lenght of the shaft. So if you consider a shorter throw to be a reduction in the angle of the shifter... you are also correct. Cutting the shifter down will not produce a different angle only a reduction in travel.

The only way to do both is to move the pivot point which is what good aftermarket shifters will do for you. This allows you to not only have a shorter "throw" but also a reduced angle allowing you to use less force than would otherwise be needed.

By moving the pivot point it is able to offset (somewhat) the increase in force required to move the shift rod through it's range of motion. This allows the overall length of the rod to be shorter without a significant increase in force.

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