 1 - 4 of 4 Posts

#### Lisa

·
##### Registered
Joined
·
54 Posts
Discussion Starter
hey people im having trouble on this one problem now for some this is very easy math but i need help on this problem its intermediate algebra heres the question.....................................................

I have a certain number of \$20 bills. I have 24 more \$10 bills than \$20 bills. The value of the \$20's equals the value of the \$10's . How many of each bill do i have ? Hint: \$20(x)=\$10(x+?)

here is the answer but i dont know how to work the problem to get the answer 24 \$20 bills, 48 \$10 bills if anyone could help that would be cool i just need an explanation to get this answer thanks

#### James

·
##### in^3,N20,RPM,PSI
Joined
·
4,652 Posts
well you have 24 20's so that equals 480 and 24 more 10's than you have 20's so that makes 48 10's which also equals 480... so it'd be 10(x+24)...

#### Lisa

·
##### Registered
Joined
·
54 Posts
Discussion Starter
ya its 10(x+24) and 20(x) so
10x+240 240 divided by 10= 24 which = how many 20\$ then 24 + 24 = 48 which equals how many 10\$ i got thanks anyway but i finally figured it out..................sorry to waste ur time....

#### rios

·
##### Registered
Joined
·
672 Posts
me + whiskey * math problems / my current patience = low  just thought id share with you all

1 - 4 of 4 Posts