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hey people im having trouble on this one problem now for some this is very easy math but i need help on this problem its intermediate algebra heres the question.....................................................



I have a certain number of $20 bills. I have 24 more $10 bills than $20 bills. The value of the $20's equals the value of the $10's . How many of each bill do i have ? Hint: $20(x)=$10(x+?)


here is the answer but i dont know how to work the problem to get the answer 24 $20 bills, 48 $10 bills if anyone could help that would be cool i just need an explanation to get this answer thanks
 

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ya its 10(x+24) and 20(x) so
10x+240 240 divided by 10= 24 which = how many 20$ then 24 + 24 = 48 which equals how many 10$ i got thanks anyway but i finally figured it out..................sorry to waste ur time....
 

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me + whiskey * math problems / my current patience = low

:D ;)
just thought id share with you all
 
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