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Forced Induction & Nitrous Oxide Turbocharger, supercharger, and nitrous oxide information

       
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Old Feb 23rd, 2003, 10:19 PM   #1 (permalink)
Murph
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what is extrude honed and housing sizes?

Can someone pls explain the "housing" of the compessor and turbine. I know what they are, but what does .65 and .83 numbers mean? The AR things?

Also, what exactly does extrude honed and such mean?

Thanks again guys.
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Old Feb 24th, 2003, 12:01 AM   #2 (permalink)
spdracerUT
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I'm pretty sure the A/R is the inlet vs. outlet sizes. And extrude honing... well, most of the parts are made from casting which leaves a rough surface. Extrude honing uses this slurry mix stuff which they flow through the part which basically polishes the surface smooth(which improves airflow, power, etc).

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Old Feb 24th, 2003, 10:35 AM   #3 (permalink)
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so if its .83 is it .83 of an inch or relative to something else?
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Old Feb 24th, 2003, 10:41 AM   #4 (permalink)
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A/R is the area of the scroll divided by the radius from the center of the scroll to the shaft centerline.
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Old Feb 24th, 2003, 03:40 PM   #5 (permalink)
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Quote:
Originally posted by James
A/R is the area of the scroll divided by the radius from the center of the scroll to the shaft centerline.
can you dim it down a shade

i dont want to be annoying, but i think im close to grapsing this.

what is the scroll?
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Old Feb 24th, 2003, 03:46 PM   #6 (permalink)
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You ever seen a sea shell cut in half?
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Old Feb 24th, 2003, 03:52 PM   #7 (permalink)
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well I gotta go soon but if you look housing sourronding the comrpessor/turbine then you'll see it looks like a shell. you take the area of the opening at any given place and divide that area by the distance of that opening to the centerline of the compressor/turbine... that's A/R area/radius
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Old Feb 24th, 2003, 04:17 PM   #8 (permalink)
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A/R is effectively the leverage the gas flow can impart to the turbine shaft, and by extension, the impeller.

A = cross-sectional area of the turbine inlet.
R = radius of the turbine.

A larger diameter turbine (bigger R) will generate more pressure than a smaller one for a given flow VELOCITY at the expense of longer spool time due to higher mass.

As A get larger, flow velocity drops for a given volume of gas but max flow goes up. Smaller A = higher velocity and more leverage on turbine for a given R but will choke at a lower total flow.

A/R = .65 should spool quickly and have good mid-range response with lower total power while the .83 A/R will be a top-end biased unit.



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Old Feb 25th, 2003, 01:12 AM   #9 (permalink)
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I GET IT

thank you so much!!
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